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Jun 15, 2020 at 7:27 history edited CommunityBot
Commonmark migration
Oct 5, 2012 at 2:10 comment added Yuhao Huang Rank one and non-zero ==> generic isomorphism, and torsion-free ==> injective (The kernel is supported on a proper closed subset, thus torsion.)
Sep 19, 2012 at 17:06 comment added 36min Thanks for pointing that out. I think rank one is also part of the definition. That's specified by the numerical class.
Sep 19, 2012 at 12:34 comment added MartinG I just had a look at the paper: Maybe this is also stated more explicitly elsewhere, but I think at least the proof of Lemma 6.3 reveals that an ideal sheaf means a torsion free sheaf for which there exists a nonzero map to $\mathcal{O}_X$, that for families, this condition is just imposed fibrewise (as Sasha suggested) and moreover that this is a closed condition. Anyway, I am leaving my answer as it is, covering the smooth case. (And I still have no idea whether the natural map could fail to be an iso in the singular case.)
Sep 19, 2012 at 6:39 history edited 36min CC BY-SA 3.0
Updated the question, hopefully it makes more sense now.
Sep 19, 2012 at 6:09 answer added Sasha timeline score: 2
Sep 18, 2012 at 17:04 answer added MartinG timeline score: 10
Sep 18, 2012 at 7:58 answer added Sándor Kovács timeline score: 8
Sep 18, 2012 at 6:46 history asked 36min CC BY-SA 3.0