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Johan
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The Schwartz kernel theorem seams relevant here. You might recall from your signal processing books that in the linear but non-time-invariant case we still get the output as a convolution of a kernel withintegral $\int K(x,y) f(y)dy$ where $f$ is the input, but a different kernel for each point in time. The kernel theorem makes this rigorous as I recall where, $K$ then can be a distribution.

Once you have that theorem it is probably easy to get the statement you want. Indeed the kernel can hardly be time-varying if the system is to be time-invariant.

The Schwartz kernel theorem seams relevant here. You might recall from your signal processing books that in the linear but non-time-invariant case we still get the output as a convolution of a kernel with the input, but a different kernel for each point in time. The kernel theorem makes this rigorous as I recall.

Once you have that theorem it is probably easy to get the statement you want. Indeed the kernel can hardly be time-varying if the system is to be time-invariant.

The Schwartz kernel theorem seams relevant here. You might recall from your signal processing books that in the linear but non-time-invariant case we still get the output as a integral $\int K(x,y) f(y)dy$ where $f$ is the input. The kernel theorem makes this rigorous as I recall where, $K$ then can be a distribution.

Once you have that theorem it is probably easy to get the statement you want.

Source Link
Johan
  • 757
  • 1
  • 5
  • 13

The Schwartz kernel theorem seams relevant here. You might recall from your signal processing books that in the linear but non-time-invariant case we still get the output as a convolution of a kernel with the input, but a different kernel for each point in time. The kernel theorem makes this rigorous as I recall.

Once you have that theorem it is probably easy to get the statement you want. Indeed the kernel can hardly be time-varying if the system is to be time-invariant.