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Sep 17, 2012 at 14:37 comment added an12 Hi Gerald. Yes, indeed, only he can say what he meant!
Sep 17, 2012 at 13:23 comment added Gerald Edgar Only Scot Free can say what he means, and he has not chosen to return and do so.
Sep 14, 2012 at 0:38 comment added an12 I don't think the question is about measures per se, but about their Radon-Nikodym derivatives with respect to their dominating measure, whatever that is. For instance, the PDF function integrating to 1 in the question can be thought of as the Radon-Nikodym derivative of some probability measure with respect to its dominating Lebesgue measure.
Sep 13, 2012 at 20:20 history answered Adrien CC BY-SA 3.0