Timeline for Is the category of vector bundles over a topological space abelian?
Current License: CC BY-SA 3.0
6 events
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Sep 13, 2012 at 16:25 | history | undeleted | Ryan Reich | ||
Sep 13, 2012 at 16:25 | history | edited | Ryan Reich | CC BY-SA 3.0 |
added 11 characters in body
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Sep 13, 2012 at 16:23 | history | deleted | Ryan Reich | ||
Sep 13, 2012 at 16:15 | comment | added | Damian Rössler | View $\bf R$ (resp. ${\bf R}^2$) as the trivial (real) vector bundle of rank $1$ (resp. rank $2$) over the real line $\bf R$, viewed as a topological space with the ordinary topology. Let $f:{\bf R}\to {\bf R}^2$ be the map of vector bundles st $f(t,v)=(t,v\cdot(t,1))$. Let $g:{\bf R}^2\to{\bf R}$ be the map of vector bundles $g(t,v,w)=(t,v)$. Then $g$ and $f$ have constant rank but $g\circ f$ does not (because $g\circ f$ restricted to $0$ as rank $0$ and not otherwise). So the class you describe is not a category. | |
Sep 13, 2012 at 16:11 | comment | added | Laurent Moret-Bailly | Unfortunately, the second category is not additive. | |
Sep 13, 2012 at 15:37 | history | answered | Ryan Reich | CC BY-SA 3.0 |