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Francesco Polizzi
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It is often easier to construct Galois covers of degree $n$.

In the case where $E$ is an elliptic curve and we have $t$ branch points, by Riemann existence theorem a Galois cover with Galois group $G$ is defined by the following data:

$\bullet$ a finite group $G$ of order $n$;

$\bullet$ elements $a, b, g_1, \ldots, g_t$ such that $G= \langle a, b, g_1, \ldots, g_t \rangle$ and $[a,b]g_1g_2 \ldots g_t=e$.

An important remark is that for a Galois cover the local monodromies around points in the same fibre are conjugate transpositions, i.e. points over the same branch points have monodromies with the same cyclic structure (this is in general false for non-Galois covers). Moreover, over the branch point $b_i$ such a structure is a cycle of order equal to the order of the element $g_i$.

Let us see now how to construct Galois coverings in the cases you are interested in.

Three branch points, that is $t=3$. For each $n$ we can construct a cyclic cover of degree $n$: simply choose $$G=\mathbb{Z}/n \mathbb{Z}=\langle x | x^n=1 \rangle $$ (I use the multiplicative notation) and take $$a=x, \quad b=x, \quad g_1=x, \quad g_2=x, \quad g_3=x^{-2}.$$

Two branch points, that is $t=2.$ Again, we have a cyclic cover for any $n$. Choose $G$ as above and take $$a=x, \quad b=x, \quad g_1=x, \quad g_2=x^{-1}$$.

One branch point, that is $t=1.$ A moment of reflection shows that we cannot take $G$ abelian in this case, otherwise $[a,b]g_1=e$ implies $g_1=e$, that is the cover would be unramified, contradiction. We can however construct a dihedral cover of degree $n=2m$ for any $m$. In fact, set $$D_{2m}= \langle x, y | x^2=y^m=1, \quad xy=y^{-1}x \rangle$$ and take $$a=x, \quad b=y, \quad g_1=y^2.$$

regarding your last comment, observe that when $m=5$ you have a Galois cover of degree $10$ with a unique branch point, whose branching order is $5$. In other words, over the unique branch point $b$ one has precisely two points $q_1, q_2$ and the local monodromy around each of the $q_i$ is by construction a $5$-cycle.

One can also construct Galois covers of odd degree with a unique branch point, for instance taking more general metacyclic groups (i.e. non-trivial semidirect products of cyclic groups). The dihedral covers are in fact a particular case of this construction.

Remark. I misread the question and I did not see the assumption that the covers must be of genus $3$. Only few of my constructions give genus $3$ curves (actually, it is not difficult to find all of them by using Hurwitz formula).

I will leave the answer anyway, since maybe it can be useful for other pourposes.

It is often easier to construct Galois covers of degree $n$.

In the case where $E$ is an elliptic curve and we have $t$ branch points, by Riemann existence theorem a Galois cover with Galois group $G$ is defined by the following data:

$\bullet$ a finite group $G$ of order $n$;

$\bullet$ elements $a, b, g_1, \ldots, g_t$ such that $G= \langle a, b, g_1, \ldots, g_t \rangle$ and $[a,b]g_1g_2 \ldots g_t=e$.

An important remark is that for a Galois cover the local monodromies around points in the same fibre are conjugate transpositions, i.e. points over the same branch points have monodromies with the same cyclic structure (this is in general false for non-Galois covers). Moreover, over the branch point $b_i$ such a structure is a cycle of order equal to the order of the element $g_i$.

Let us see now how to construct Galois coverings in the cases you are interested in.

Three branch points, that is $t=3$. For each $n$ we can construct a cyclic cover of degree $n$: simply choose $$G=\mathbb{Z}/n \mathbb{Z}=\langle x | x^n=1 \rangle $$ (I use the multiplicative notation) and take $$a=x, \quad b=x, \quad g_1=x, \quad g_2=x, \quad g_3=x^{-2}.$$

Two branch points, that is $t=2.$ Again, we have a cyclic cover for any $n$. Choose $G$ as above and take $$a=x, \quad b=x, \quad g_1=x, \quad g_2=x^{-1}$$.

One branch point, that is $t=1.$ A moment of reflection shows that we cannot take $G$ abelian in this case, otherwise $[a,b]g_1=e$ implies $g_1=e$, that is the cover would be unramified, contradiction. We can however construct a dihedral cover of degree $n=2m$ for any $m$. In fact, set $$D_{2m}= \langle x, y | x^2=y^m=1, \quad xy=y^{-1}x \rangle$$ and take $$a=x, \quad b=y, \quad g_1=y^2.$$

regarding your last comment, observe that when $m=5$ you have a Galois cover of degree $10$ with a unique branch point, whose branching order is $5$. In other words, over the unique branch point $b$ one has precisely two points $q_1, q_2$ and the local monodromy around each of the $q_i$ is by construction a $5$-cycle.

One can also construct Galois covers of odd degree with a unique branch point, for instance taking more general metacyclic groups (i.e. non-trivial semidirect products of cyclic groups). The dihedral covers are in fact a particular case of this construction.

It is often easier to construct Galois covers of degree $n$.

In the case where $E$ is an elliptic curve and we have $t$ branch points, by Riemann existence theorem a Galois cover with Galois group $G$ is defined by the following data:

$\bullet$ a finite group $G$ of order $n$;

$\bullet$ elements $a, b, g_1, \ldots, g_t$ such that $G= \langle a, b, g_1, \ldots, g_t \rangle$ and $[a,b]g_1g_2 \ldots g_t=e$.

An important remark is that for a Galois cover the local monodromies around points in the same fibre are conjugate transpositions, i.e. points over the same branch points have monodromies with the same cyclic structure (this is in general false for non-Galois covers). Moreover, over the branch point $b_i$ such a structure is a cycle of order equal to the order of the element $g_i$.

Let us see now how to construct Galois coverings in the cases you are interested in.

Three branch points, that is $t=3$. For each $n$ we can construct a cyclic cover of degree $n$: simply choose $$G=\mathbb{Z}/n \mathbb{Z}=\langle x | x^n=1 \rangle $$ (I use the multiplicative notation) and take $$a=x, \quad b=x, \quad g_1=x, \quad g_2=x, \quad g_3=x^{-2}.$$

Two branch points, that is $t=2.$ Again, we have a cyclic cover for any $n$. Choose $G$ as above and take $$a=x, \quad b=x, \quad g_1=x, \quad g_2=x^{-1}$$.

One branch point, that is $t=1.$ A moment of reflection shows that we cannot take $G$ abelian in this case, otherwise $[a,b]g_1=e$ implies $g_1=e$, that is the cover would be unramified, contradiction. We can however construct a dihedral cover of degree $n=2m$ for any $m$. In fact, set $$D_{2m}= \langle x, y | x^2=y^m=1, \quad xy=y^{-1}x \rangle$$ and take $$a=x, \quad b=y, \quad g_1=y^2.$$

regarding your last comment, observe that when $m=5$ you have a Galois cover of degree $10$ with a unique branch point, whose branching order is $5$. In other words, over the unique branch point $b$ one has precisely two points $q_1, q_2$ and the local monodromy around each of the $q_i$ is by construction a $5$-cycle.

One can also construct Galois covers of odd degree with a unique branch point, for instance taking more general metacyclic groups (i.e. non-trivial semidirect products of cyclic groups). The dihedral covers are in fact a particular case of this construction.

Remark. I misread the question and I did not see the assumption that the covers must be of genus $3$. Only few of my constructions give genus $3$ curves (actually, it is not difficult to find all of them by using Hurwitz formula).

I will leave the answer anyway, since maybe it can be useful for other pourposes.

Source Link
Francesco Polizzi
  • 66.3k
  • 5
  • 180
  • 283

It is often easier to construct Galois covers of degree $n$.

In the case where $E$ is an elliptic curve and we have $t$ branch points, by Riemann existence theorem a Galois cover with Galois group $G$ is defined by the following data:

$\bullet$ a finite group $G$ of order $n$;

$\bullet$ elements $a, b, g_1, \ldots, g_t$ such that $G= \langle a, b, g_1, \ldots, g_t \rangle$ and $[a,b]g_1g_2 \ldots g_t=e$.

An important remark is that for a Galois cover the local monodromies around points in the same fibre are conjugate transpositions, i.e. points over the same branch points have monodromies with the same cyclic structure (this is in general false for non-Galois covers). Moreover, over the branch point $b_i$ such a structure is a cycle of order equal to the order of the element $g_i$.

Let us see now how to construct Galois coverings in the cases you are interested in.

Three branch points, that is $t=3$. For each $n$ we can construct a cyclic cover of degree $n$: simply choose $$G=\mathbb{Z}/n \mathbb{Z}=\langle x | x^n=1 \rangle $$ (I use the multiplicative notation) and take $$a=x, \quad b=x, \quad g_1=x, \quad g_2=x, \quad g_3=x^{-2}.$$

Two branch points, that is $t=2.$ Again, we have a cyclic cover for any $n$. Choose $G$ as above and take $$a=x, \quad b=x, \quad g_1=x, \quad g_2=x^{-1}$$.

One branch point, that is $t=1.$ A moment of reflection shows that we cannot take $G$ abelian in this case, otherwise $[a,b]g_1=e$ implies $g_1=e$, that is the cover would be unramified, contradiction. We can however construct a dihedral cover of degree $n=2m$ for any $m$. In fact, set $$D_{2m}= \langle x, y | x^2=y^m=1, \quad xy=y^{-1}x \rangle$$ and take $$a=x, \quad b=y, \quad g_1=y^2.$$

regarding your last comment, observe that when $m=5$ you have a Galois cover of degree $10$ with a unique branch point, whose branching order is $5$. In other words, over the unique branch point $b$ one has precisely two points $q_1, q_2$ and the local monodromy around each of the $q_i$ is by construction a $5$-cycle.

One can also construct Galois covers of odd degree with a unique branch point, for instance taking more general metacyclic groups (i.e. non-trivial semidirect products of cyclic groups). The dihedral covers are in fact a particular case of this construction.