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Sep 10, 2012 at 21:25 comment added Gene Ward Smith The point is, if you have F/Q(t) with Galois group G, specializing t to a value in Q leads to an extension K/Q with Galois group G in nearly all cases. Hence it's a sort of machine for cranking out endless examples. It is particularly nice if F contains no algebraic extension of Q, as then the examples your machine cranks out don't share a common extension of Q.
Sep 10, 2012 at 14:43 comment added Todd Trimble I had assumed OP meant over $\mathbb{Q}$, although I grant you that wasn't specified in the question.
Sep 10, 2012 at 4:34 history answered Gene Ward Smith CC BY-SA 3.0