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Sep 13, 2012 at 23:12 history edited Karl Schwede
fixed a tag
Sep 6, 2012 at 11:50 comment added Laurent Berger If you're looking at linear representations of $G$ with coefficients, then everything works "the same". See for example 3.1 of Breuil-Mézard's 2002 Duke paper.
Sep 6, 2012 at 7:45 vote accept TOM
Sep 6, 2012 at 12:00
Sep 6, 2012 at 7:18 comment added TOM I am sorry, F should be a subfield of K.
Sep 6, 2012 at 7:15 comment added Laurent Berger You also changed the setting completely. Is $F$ an extension of $K$ or a subfield of $K$??
Sep 6, 2012 at 7:13 history edited TOM CC BY-SA 3.0
added 111 characters in body
Sep 6, 2012 at 7:09 comment added TOM I have edited it to more easy case.
Sep 6, 2012 at 7:07 history edited TOM CC BY-SA 3.0
added 11 characters in body; added 20 characters in body
Sep 6, 2012 at 7:06 answer added Laurent Berger timeline score: 3
Sep 6, 2012 at 2:57 history edited TOM CC BY-SA 3.0
edited title
Sep 6, 2012 at 0:55 history asked TOM CC BY-SA 3.0