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Sep 5, 2012 at 15:14 comment added Deane Yang Otis, agreed. Just wanted it stated explicitly. On the other hand, it would be best if the original poster just worked out the proof and figured this out independently.
Sep 5, 2012 at 14:12 comment added Otis Chodosh @Deane, I believe @Bazin means for any $N$ (of course the constant $C$ depends on $N$ as indicated), so it says that the $L^2\to L^2$ norm decays "rapidly" in $|j-k|$.
Sep 5, 2012 at 13:14 comment added Deane Yang What if anything does $N$ depend on in the displayed inequality?
Sep 5, 2012 at 12:35 history answered Bazin CC BY-SA 3.0