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Sep 7, 2012 at 5:58 vote accept ronggang
Sep 3, 2012 at 21:44 history edited grp CC BY-SA 3.0
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Sep 3, 2012 at 20:59 comment added Jim Humphreys At the outset of his Corvallis survey, Tits only requires $G$ to be an algebraic group defined over $K$ whose identity component is reductive. But this much generality is bound to create occasional technical problems later on. Anyway, these notes as well as the research papers are definitely challenging, even if the reader first thinks about just a well-behaved low rank group.
Sep 3, 2012 at 19:49 history edited grp CC BY-SA 3.0
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Sep 3, 2012 at 19:06 history answered grp CC BY-SA 3.0