Skip to main content
5 events
when toggle format what by license comment
Jan 4, 2010 at 23:54 comment added David Zureick-Brown (No guarantee on that last sentence).
Jan 4, 2010 at 23:53 comment added David Zureick-Brown Ah, so in that case the fibers are gerbes (and I think the total space is a gerbe). In general, the coarse space does not represent the functor you wrote down; it is an intermediate step in proving that a coarse space exists, but you may still need too modify that functor more. Even for M_1,1 I believe the coarse space differs from this functor. For instance, two families of curves with the same `j-invariant' give the same map to M_1,1, but there isn't necessarily a flat cover of the base where they become isomorphic (though there is on some open subset of the base).
Jan 4, 2010 at 0:43 comment added shenghao I seem to remember this from the book <champs algebrique> by LMB. 1. In the book, a coarse moduli space of a stack XX is defined to be the functor X sending U to the set of isom classes in XX(U). And XX->X is a gerbe. When XX is DM over k, I guess (without checking details) these two notions agree. 2. At least for any field-valued pt x:Spec k -> X, the fiber f^{-1}(x) is a fppf-gerbe over x (fppf-locally there exists an obj over x, and any two objects are isomorphic over \bar{k}, hence isom over some finite ext'n of k), and therefore smooth. Does this imply that f is smooth?
Jan 3, 2010 at 23:07 comment added David Zureick-Brown Why is XX --> X a gerbe?
Jan 3, 2010 at 21:22 history answered shenghao CC BY-SA 2.5