Timeline for What's an example of a transcendental power series?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Jun 25, 2013 at 3:02 | review | Late answers | |||
| Jun 27, 2013 at 10:37 | |||||
| Sep 2, 2012 at 4:46 | comment | added | Todd Trimble | @camilo: the series of Marc is not periodic and has integer coefficients. How can you claim not integer coefficients?! Are you not understanding the notation? Maybe you think his $i$ stands for the square root of minus 1, and totally misunderstood?? | |
| Sep 1, 2012 at 23:57 | comment | added | Vladimir Dotsenko | Your claims are dramatically wrong, or else you are using many conventional words with seriously unconventional meanings. | |
| Sep 1, 2012 at 21:46 | comment | added | camilo | this serie is trivially periodic, and dont have integer coeficent . | |
| Sep 1, 2012 at 21:42 | comment | added | Marc van Leeuwen | Certainly $\frac1{(1-t)^2}=\sum_i(i+1)t^i$ is not transcendental over $\mathbf Q[t]$, is it?? (And you can type dollars to get math; the converse unfortunately doesn't work;-) | |
| Sep 1, 2012 at 21:37 | comment | added | camilo | For a best example you can see that if $y(t)=\sum a_it^i$ and $f(t,y)=0$ with $f$ a polinomial in two variables you can see the set of $x$ such that $y(x)=1$ is the set of $t$ with $f(t,1)=0$ that is finite, so every y(x) with this set infinite isn´t algebraic particularly $y(t)=e^t$ | |
| Sep 1, 2012 at 20:55 | history | answered | camilo | CC BY-SA 3.0 |