Timeline for Is it possible to represent non-linear ranking type constraints as equivalent linear constraints?
Current License: CC BY-SA 3.0
5 events
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| Feb 3, 2015 at 9:28 | answer | added | J Fabian Meier | timeline score: 2 | |
| Sep 3, 2012 at 11:45 | comment | added | stressed_geek | Yes, you are correct, the second constraint is a trivial onsequence of the definitions of $z^1_{ij}(a)$ and $z^2_{ij}(a)$. That is why I am looking for stronger linear constraints. | |
| Sep 2, 2012 at 3:14 | comment | added | Brian Borchers | You haven't mentioned this, but it would seem obvious that you want the additional constraint that $\sum_{b} z_{j}(b)=1$. That is, document j has exactly one rank. Once you've added that constraint, the second constraint $z_{ij}^{1}(a)+z_{ij}^{2}(a)=z_{i}(a)$ is a trivial consequence of the definitions of $z_{ij}(a)^{1}$ and $z_{ij}(a)^{2}$. | |
| Sep 1, 2012 at 18:58 | history | edited | stressed_geek | CC BY-SA 3.0 |
deleted 32 characters in body; added 26 characters in body; added 2 characters in body
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| Sep 1, 2012 at 18:53 | history | asked | stressed_geek | CC BY-SA 3.0 |