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Jul 23, 2019 at 17:37 answer added Michael Engelhardt timeline score: 1
Jul 23, 2019 at 16:17 answer added Georg Essl timeline score: 2
Jul 3, 2017 at 4:17 answer added Phil Harmsworth timeline score: 5
Sep 23, 2015 at 7:42 comment added user13113 I personally find multivariable calculus already better formulated in terms of covectors rather than vectors; IMO the exterior derivative is more natural than directional derivatives, especially in terms of symbolic calculation, and furthermore $\mathrm{d}(xy)$ is always $y \mathrm{d}x + x \mathrm{d}y$, whereas there are several relevant ways in which $\frac{\partial}{\partial x}(xy)$ won't be $y$ (e.g. if $y$ depends on $x$, or you are working in different coordinates and mean to hold $x-y$ constant rather than holding $y$ constant).
May 31, 2015 at 19:03 comment added Norbert @StevenGubkin I was waiting for this explanation for years!
Oct 7, 2013 at 2:46 history edited Ricardo Andrade
replaced tag 'tag-removed'
Oct 7, 2013 at 2:26 answer added Douglas Lind timeline score: 6
Oct 6, 2013 at 22:30 history edited Michael Albanese CC BY-SA 3.0
Replace &nbsp by \ so math would render properly. There should probably be some wedges in there as well, but I wasn't sure if the OP was supressing specific notation for the multiplicative structure on \Omega(M).
Jul 7, 2012 at 10:52 answer added Mirco A. Mannucci timeline score: 42
Dec 1, 2011 at 2:42 answer added Phil Isett timeline score: 12
Jan 27, 2011 at 20:25 comment added Steven Gubkin A 1-form is a function which grows proportionally to how fast you are moving. Thus it doesn't matter how you parametrize the curve you are moving on - you either end up integrating a smaller function for a longer period of time, or a bigger function for a shorter period of time. This is why you can't integrate functions on manifolds - they have no intrinsic "unit speeds", because there are many choices of local coordinates - but you can still integrate differential forms. k-forms just generalize this to higher dimensions.
Jul 12, 2010 at 7:15 answer added Jonathan Fischoff timeline score: 6
Feb 11, 2010 at 17:01 answer added Olivier timeline score: 10
Jan 14, 2010 at 22:53 comment added B. Bischof +1 for "I freaking love this question".
Jan 3, 2010 at 22:32 history made wiki Post Made Community Wiki by Qiaochu Yuan
Jan 3, 2010 at 21:21 answer added Mike Shulman timeline score: 9
Jan 3, 2010 at 19:04 answer added Ilya Grigoriev timeline score: 28
Jan 3, 2010 at 15:43 answer added pmoduli timeline score: 7
Jan 3, 2010 at 15:28 comment added Akhil Mathew Have you seen From Calculus to Cohomology by Madsden and Tornehave? It's not really about physical intuition (which is why I'm making this a comment), but it might be helpful.
Jan 3, 2010 at 15:24 answer added S. Carnahan timeline score: 5
Jan 3, 2010 at 15:22 answer added Matt Noonan timeline score: 8
Jan 3, 2010 at 15:04 answer added David Lehavi timeline score: 6
Jan 3, 2010 at 14:26 answer added José Figueroa-O'Farrill timeline score: 116
Jan 3, 2010 at 13:52 answer added Deane Yang timeline score: 7
Jan 3, 2010 at 13:17 answer added Steve Huntsman timeline score: 5
Jan 3, 2010 at 13:12 answer added Harrison Brown timeline score: 23
Jan 3, 2010 at 12:22 comment added Pete L. Clark This is nitpicky, but it is traditional to denote the product structure on differential forms with a $\wedge$ ("wedge product").
Jan 3, 2010 at 10:55 answer added Thomas Sauvaget timeline score: 12
Jan 3, 2010 at 10:11 history asked Qiaochu Yuan CC BY-SA 2.5