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Aug 28, 2012 at 18:42 comment added Noah Stein Could you explain how the first sentence of my previous comment does not answer your most recent update?
Aug 28, 2012 at 17:34 history edited Felix Goldberg CC BY-SA 3.0
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Aug 28, 2012 at 14:00 comment added Suvrit Yep: suppose $A$ is a diagonal matrix with $-1$ as its 1st entry, and all other entries zero. Then, clearly let $X=tI$, with $t\to \infty$ makes the problem unbounded below, and there is no minimum. The infimum is $-\infty$. So the problem needs either a compact set or some other modifications before it is well-posed.
Aug 28, 2012 at 12:26 comment added Noah Stein If I understand the problem correctly, can't you minimize $(AX)_{ii}$ over the psd cone for each $i$ individually and then take the $i$ which makes this smallest? Of course, since the set of psd matrices is a cone and scaling $X$ scales your objective, you will either get an optimal value of $0$ achieved at $0$ (or as you approach $0$ if you are interested in the infimum and not including zero) or else the infimum will be $-\infty$.
Aug 28, 2012 at 11:43 history edited Felix Goldberg CC BY-SA 3.0
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Aug 28, 2012 at 11:37 comment added Suvrit Since it is in general NP-hard, it is of value to look at the specific case that you might have; perhaps that may be amenable to a global solution, or at least a good approximation algorithm....(if the solution exists at all)
Aug 28, 2012 at 11:33 comment added Felix Goldberg Yes, I understand it'd be hard:) That's why i want to know if there are some approaches people have developed to this kind of problem. Thanks!
Aug 28, 2012 at 11:33 answer added none timeline score: -1
Aug 28, 2012 at 11:28 comment added Suvrit it would be beneficial to see the explicit formulation. But since you are trying to minimize a concave function it won't be that easy....
Aug 28, 2012 at 11:03 history asked Felix Goldberg CC BY-SA 3.0