Skip to main content

Timeline for about relative homotopy group

Current License: CC BY-SA 3.0

3 events
when toggle format what by license comment
Nov 27, 2017 at 20:08 comment added Omar Antolín-Camarena @GregFriedman This is that argument, just phrased differently. (In particular $\Omega \Sigma \mathbb{R}P^2 \times \mathbb{R}P^2$ being connected is equivalent to $\pi_0(\mathbb{R}P^2)$ and $\pi_1(S(RP^2))$ being trivial.)
Aug 27, 2012 at 21:11 comment added Greg Friedman This seems like overkill to me. Why not just use the long exact sequence of the pair and that $\pi_0(RP^2)$ and $pi_1(S(RP^2))$ are trivial?
Aug 26, 2012 at 15:46 history answered Jeff Strom CC BY-SA 3.0