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Aug 26, 2012 at 14:36 history edited Felipe Voloch CC BY-SA 3.0
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Aug 26, 2012 at 14:09 comment added Jason Starr @Felipe: The best result I know of is the result of Geng Xu cited by the OP. However, as the OP remarks, this only applies to "very general" surfaces, so potentially might fail for <I>every</I> surface defined over a number field.
Aug 26, 2012 at 13:26 comment added Felipe Voloch @Jason: Good point. Can these be ruled out separately?
Aug 26, 2012 at 13:11 comment added Jason Starr I'm not sure what you write is correct. Certainly a smooth rational or elliptic curve would give a divisor class on the general type hypersurface that is not commensurable with the hyperplane class. However, these surfaces may contain singular curves whose normalization has geometric genus $0$ or $1$ and whose divisor classes are multiples of the hyperplane class.
Aug 26, 2012 at 13:01 history answered Felipe Voloch CC BY-SA 3.0