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Aug 27, 2012 at 9:33 vote accept domotorp
Aug 26, 2012 at 7:09 comment added domotorp Okay, the Edit part answers my original question. In this construction the uncovered part is a high dim manifold stretching to every face. So can we guarantee the existence of something like this? I know this is a vague question...
Aug 26, 2012 at 6:48 comment added domotorp I still think that we have a misunderstanding, probably I should not have called it affine subspace of S but rather subspace of S. I have tried to make the def in the original post more clear. Do you see the problem now or is it my bad and am I missing something?
Aug 25, 2012 at 21:55 history edited Ilya Bogdanov CC BY-SA 3.0
some counterexamples added
Aug 25, 2012 at 21:43 comment added Ilya Bogdanov Where is a misunderstanding? The intersection of $V$ with $S$ is exactly a small piece contained in $U(s)$. You may consider also the linear hull of $V$ --- it changes nothing since $S$ lies in $\mathop{\rm aff}\{e_i\colon i\in [n+1]\}$. .
Aug 25, 2012 at 20:58 comment added domotorp I think there is a misunderstanding in the definition of my definition of k-dim affine subspace of S. It must the whole intersection of S and a linear subspace.
Aug 25, 2012 at 20:10 history answered Ilya Bogdanov CC BY-SA 3.0