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Jul 28, 2019 at 14:23 history edited J. M. isn't a mathematician CC BY-SA 4.0
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Aug 26, 2012 at 1:19 comment added user9072 Thanks for the hints. (I will refrain from editing at least for the moent; but good to know for the future).
Aug 25, 2012 at 10:09 comment added Américo Tavares To get $\binom{2n}{n}$ I've used \binom{2n}{n}.
Aug 25, 2012 at 3:19 comment added Lunasaurus Rex You could use(^{2n}_{n}) to get $(^{2n}_{n})$
Aug 24, 2012 at 21:22 history answered user9072 CC BY-SA 3.0