Skip to main content

Timeline for Loop space: De Rham cohomology

Current License: CC BY-SA 3.0

5 events
when toggle format what by license comment
Aug 30, 2012 at 3:27 comment added Somnath Basu @John, eigenbunny - If $M$ is not simply connected then $LM$ is not connected; therefore, $\pi_1(LM)$ is meaningless unless you specify which component. The constant section only provides a section for $L_0M \to M$, where $L_0 M$ is the component of constant loops. The components of $LM$ are indexed by the conjugacy classes in $\pi_1(M)$.
Aug 26, 2012 at 4:03 comment added John Klein @eigenbunny: Note: your short exact sequence comes equipped with a section $\pi_1(M) \to \pi_1(LM)$ induced by the inclusion of constant loops. Hence $\pi_1(LM)$ is a semi-direct product of $\pi_1(M)$ by $\pi_2(M)$.
Aug 23, 2012 at 22:38 comment added Mark Grant +1 for "see by hand" :)
Aug 23, 2012 at 21:09 comment added Somnath Basu It's better to say why the base point fibration (you perhaps mean the loop space fibration $\Omega M\to LM\to M$) gives a short exact sequence. In general, you get a long exact sequence; here it splits to short exact sequence as the fibration has a section. Another point to note is that $LM$ is not connected if $M$ has a fundamental group.
Aug 23, 2012 at 20:27 history answered eigenbunny CC BY-SA 3.0