Timeline for Basis of a group
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
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| Aug 15, 2012 at 12:26 | vote | accept | Klim Efremenko | ||
| Aug 14, 2012 at 20:54 | history | edited | Benjamin Steinberg |
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| Aug 14, 2012 at 20:53 | answer | added | Benjamin Steinberg | timeline score: 6 | |
| Aug 14, 2012 at 17:47 | history | edited | Chris Gerig |
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| Aug 14, 2012 at 13:14 | comment | added | Klim Efremenko | Because I believe that representation theory and lie groups may help to solve this problem. But may be it is not sufficient reason to tag it. | |
| Aug 14, 2012 at 12:40 | comment | added | Frieder Ladisch | Why the tags "lie-groups" and "rt.representation-theory"? | |
| Aug 14, 2012 at 10:15 | comment | added | Klim Efremenko | The name basis of a group I invented just now, may be this notion have an other name in the literature. | |
| Aug 14, 2012 at 10:11 | comment | added | Klim Efremenko | To Florian Eisele: thanks for a comment I made a change. | |
| Aug 14, 2012 at 10:06 | history | edited | Klim Efremenko | CC BY-SA 3.0 |
added 54 characters in body
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| Aug 14, 2012 at 9:57 | comment | added | HJRW | Evidently your basis must contain all maximal subgroups. A little googling finds that Liebeck, Praeger and Saxl have a result describing almost all the maximal subgroups of the symmetric and alternating groups. The description is rather complicated, but you could probably use it to get a lower bound. | |
| Aug 14, 2012 at 9:56 | comment | added | Florian Eisele | On the abelian case: The maximal subgroups do not form a basis. Think of a cyclic group of prime power order, where the subgroups form a chain and hence you need all of them in a basis (though I think your upper bound would still hold). | |
| Aug 14, 2012 at 9:45 | history | asked | Klim Efremenko | CC BY-SA 3.0 |