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Aug 16, 2012 at 14:29 comment added Damian Rössler In case you are still interested, the standard conjectures imply the following $$ {\rm dim}_{\bf Q}(H^a(X,\Omega^a)\cap H^{2a}(X({\bf C}),{\bf Q}))= {\rm dim}_{\bf Q}(H^a(X_\sigma,\Omega^a)\cap H^{2a}(X_\sigma({\bf C}),{\bf Q})) $$ for any $\sigma\in{\rm Aut}({\bf C})$ and $a\geq 0$.
Aug 13, 2012 at 12:18 vote accept o a
Aug 13, 2012 at 7:40 comment added Damian Rössler In this context, you might be interested in the notion of "absolute Hodge cycle", introduced by Deligne in his article "Hodge cycles on abelian varieties" (notes by J. Milne).
Aug 12, 2012 at 16:47 answer added Donu Arapura timeline score: 9
Aug 12, 2012 at 15:55 comment added Will Sawin They are because they are the dimension of algebraically defined vector spaces.
Aug 12, 2012 at 15:43 history edited o a CC BY-SA 3.0
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Aug 12, 2012 at 15:29 comment added o a Will Sawin: what does it mean 'the structure factors through the automorphism' $\sigma$ ; in what sense ? Then I am still confused whether Hodge numbers are preserved...
Aug 12, 2012 at 15:09 history edited o a CC BY-SA 3.0
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Aug 12, 2012 at 15:04 comment added o a maybe this is just a confusion/silliness on my part, I admit...
Aug 12, 2012 at 15:04 comment added o a Jason Starr: what is the answer to that part ? Do you mean to say that $dim_C H^a(X,Ω^b_X)$ is a definition of these numbers in algebraic de Rham cohomology ?
Aug 12, 2012 at 14:33 comment added Jason Starr I think you should reconsider your first question, "For example ..." (the answer is very easy).
Aug 12, 2012 at 14:24 history asked o a CC BY-SA 3.0