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Aug 10, 2012 at 18:19 answer added Youngsu timeline score: 0
Aug 10, 2012 at 13:40 answer added Mohan timeline score: 4
Aug 10, 2012 at 12:45 comment added Pham Hung Quy Could you give the reference for the claim: If $R$ is local then $I$ generated by a regular sequence?
Aug 10, 2012 at 7:49 comment added J.C. Ottem What do you mean by '$R$ is already local'?
Aug 10, 2012 at 3:52 comment added David White It's pretty late here, so I hope this isn't completely nonsensical. A Gorenstein ring is Cohen-Macaulay and both $R_m$ and $R$ are local Gorenstein and so local Cohen-Macaulay. For such rings any ideal $I$ has height equal to the depth of $I$ with respect to $I$. See e.g. en.wikipedia.org/wiki/Height_(ring_theory). Also, all regular sequences in $I$ have length equal to the depth of $I$, see en.wikipedia.org/wiki/Depth_(algebra). Now, $R$ is already local, so it seems height = depth = length of longest regular sequence even without this bit about $R_m$. How does that sound?
Aug 10, 2012 at 2:59 history asked Xingting CC BY-SA 3.0