Timeline for Are open convex PL subsets of R^n PL homeomorphic to R^n?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
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| Aug 24, 2012 at 9:15 | comment | added | Misha | @Igor: Because everybody makes it at first, I guess. It is also easily correctable (after you take a subdivision the projection induces an isomorphism of simplicial complexes). | |
| Aug 10, 2012 at 15:29 | comment | added | Igor Rivin | @Misha: why is this called the standard mistake? | |
| Aug 10, 2012 at 6:51 | comment | added | Misha | This can be proven by the "standard mistake" in PL topology (radial projection to the simplex). Standard mistake argument is, I think, in Rourke-Sanderson. Incidentally, you do not need the boundary to be PL since every convex solid is a limit of convex polytopes and so you can view your solid as a union of a convex polytope and infinitely many polyhedral annuli. | |
| Aug 9, 2012 at 23:42 | comment | added | Anton Petrunin | I do not know a reference, but it seems to be easy to prove. | |
| Aug 9, 2012 at 22:58 | history | asked | Greg Friedman | CC BY-SA 3.0 |