Timeline for Universal enveloping ring–symmetric algebra isomorphism for Lie rings
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 10, 2013 at 15:38 | comment | added | Pasha Zusmanovich | Paper by Cohn: justpasha.org/math/links/files/c/cohn/197.pdf | |
| Feb 14, 2013 at 14:50 | comment | added | Duchamp Gérard H. E. | Does somebody have the paper by by Lazard ? (I cannot find it) Sur les algebres enveloppantes universelles de certaines algebres de Lie, M Lazard - Publ. Sci. Univ. Alger. Ser. A, 1954 | |
| Feb 14, 2013 at 14:30 | comment | added | Duchamp Gérard H. E. | Does somebody has the paper by Cohn ? | |
| Aug 9, 2012 at 12:03 | comment | added | grok | @Dotsenko: yes indeed. Most people seek an algebra isomorphism, so replace $U(g)$ by an associated graded; I'm interested in less, but don't want to pass to an associated graded. My question only makes sense for Lie rings with $\mathbb Z$ or $\mathbb Z/q$ additive factors with $q$ non-prime. | |
| Aug 8, 2012 at 12:29 | comment | added | Vladimir Dotsenko | @grok: I see what you're saying - that in PM Cohn's example you will say that both are, as abelian groups, countably dimensional vector spaces over $\mathbb{F}_p$, and hence isomorphic? | |
| Aug 8, 2012 at 11:30 | comment | added | grok | It fails in the category of "algebras over $\Phi$", for some rings $\Phi$ that contain zero divisors; however, this is not exactly the question I wanted to ask; I added a clarification. | |
| Aug 6, 2012 at 15:13 | comment | added | Vladimir Dotsenko | Oh I mean, in Cohn it is shown that it fails. Under the $\mathbb{Z}$-module freeness, it is an easy exercise which is done in way too many textbooks. | |
| Aug 6, 2012 at 15:02 | comment | added | darij grinberg | I don't think this is claimed anywhere in Cohn. | |
| Aug 6, 2012 at 14:18 | history | answered | Vladimir Dotsenko | CC BY-SA 3.0 |