Timeline for Is the condition ``adjoint action does not have eigenvalue $-1$" dense in a Lie group?
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| May 30, 2019 at 0:07 | comment | added | LSpice | Although it's almost certainly clear, I did a double take: in "If $\pi_0(G)$ is odd, it's dense", 'it' is "the set satisfying the given condition" (no eigenvalue $-1$ for the adjoint action on the Lie algebra), not $\pi_0(G)$ (which wouldn't make sense anyway). (And of course "$\pi_0(G)$ is odd" really means "$\operatorname{card} $\pi_0(G)$ is odd".) | |
| Jun 20, 2014 at 11:16 | vote | accept | Xin Nie | ||
| Jun 20, 2014 at 11:20 | |||||
| Aug 6, 2012 at 2:45 | history | answered | Will Sawin | CC BY-SA 3.0 |