Timeline for Strong monotone limits and dense subalgebras of von Neumann algebras, again
Current License: CC BY-SA 3.0
4 events
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Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
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Aug 5, 2012 at 18:07 | comment | added | Nik Weaver | (In both cases, you can find a counterexample where $S$ contains no comparable elements, hence $S = S^m = S_m$ trivially.) | |
Aug 5, 2012 at 15:44 | comment | added | Nik Weaver | No in both cases. Again, check the commutative case first! | |
Aug 5, 2012 at 14:36 | history | answered | Masayoshi Kaneda | CC BY-SA 3.0 |