Timeline for When is the degree of this number 3?
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 6, 2012 at 9:10 | vote | accept | Ricky | ||
| Aug 5, 2012 at 7:43 | comment | added | Ricky | @Noam: You are right, I have corrected the formula. Thanks! | |
| Aug 5, 2012 at 7:42 | history | edited | Ricky | CC BY-SA 3.0 |
edited body
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| Aug 5, 2012 at 2:41 | answer | added | Will Sawin | timeline score: 7 | |
| Aug 4, 2012 at 20:01 | comment | added | Noam D. Elkies | $\root 3 \of{3\alpha_2^3}$ cannot be rational unless $\alpha_2 = 0$. Presumably you mean $\root 3 \of{3\alpha_2^2}$, as in the previous displayed equation, and then the general solution is $\alpha_2 = 3\beta^3$, $\root 3 \of{3\alpha_2^2} = 3 \beta^2$. | |
| Aug 4, 2012 at 19:41 | answer | added | vAx5CbcXgWD0smA9tWxF | timeline score: 0 | |
| Aug 4, 2012 at 19:01 | comment | added | Igor Rivin | Random comment: trying out random integers for a, b, shows that the degree of the minimal polynomial is usually 18 (this is in mathematica, using MinimalPolynomial[]) | |
| Aug 4, 2012 at 18:08 | history | asked | Ricky | CC BY-SA 3.0 |