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Aug 2, 2012 at 11:14 history edited Anton Petrunin CC BY-SA 3.0
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Aug 2, 2012 at 9:57 comment added Anton Petrunin @Pete, $f(z)=\bar z/\sqrt{|z|}$.
Aug 2, 2012 at 5:53 history edited Pete L. Clark CC BY-SA 3.0
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Aug 1, 2012 at 23:36 comment added Pete L. Clark Can you give an example in which there is a fixed point which is not attracting?
Aug 1, 2012 at 23:33 vote accept Pete L. Clark
Aug 1, 2012 at 23:31 comment added Pete L. Clark I guess you mean $\sqrt{|z|}$ intead of $\sqrt{z}$. Anyway, thanks: this gives a simple negative answer to all three questions.
Aug 1, 2012 at 23:29 history edited Anton Petrunin CC BY-SA 3.0
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Aug 1, 2012 at 23:02 history answered Anton Petrunin CC BY-SA 3.0