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Timeline for compact quotient

Current License: CC BY-SA 3.0

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Aug 2, 2012 at 3:58 comment added Nik Weaver Oh, you're right. So let me think about whether my counterexample can be modified to be locally compact.
Aug 2, 2012 at 2:22 comment added Noah Stein The quotient map $f: [0,1]\to S^1$ which glues $0$ to $1$ is not open: $f^{-1}\left(f\left([0,\delta)\right)\right)$ contains $1$ but does not contain $(1-\epsilon,1]$ for any $\epsilon$.
Aug 1, 2012 at 23:23 comment added Nik Weaver Quotient maps are always open, aren't they? So I think you've shown there is no locally compact counterexample.
Aug 1, 2012 at 23:00 history answered Ian Agol CC BY-SA 3.0