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Jun 20, 2016 at 22:39 comment added Tong How to prove that any $\mathbb{P}^n$ is finitely covered by an Abelian variety of the same dimension? Maybe it is elementary, but I can not see it.
Aug 1, 2012 at 14:35 comment added Jason Starr @ulrich -- I agree.
Aug 1, 2012 at 13:33 comment added naf Your argument works for any abelian variety of dimension at least $3$: by Riemann-Roch, $g!$ divides $D^g$ for any ample divisor $D$. One can also eliminate the $g=2$ case using the fact that any double cover of $\mathbb{P}^2$ with trivial canonical bundle is a $K3$ surface.
Aug 1, 2012 at 13:22 vote accept Harry
Aug 1, 2012 at 13:13 history edited Jason Starr CC BY-SA 3.0
One clarification
Aug 1, 2012 at 13:04 history answered Jason Starr CC BY-SA 3.0