Timeline for Equations for abelian coverings of $\mathbb{P^{1}}$
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
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| Jul 28, 2012 at 15:20 | comment | added | Will Sawin | Yes, since intermediate covers correspond to subgroups of the Galois group. Take the kernel onto the projection of each cyclic factor, and then take the fiber product. | |
| Jul 28, 2012 at 8:14 | comment | added | Jack | I don't know, my own guess was that the formula should look like this. But is it a well known theorem that every abelian covers are fiber product of the cyclic ones? | |
| Jul 27, 2012 at 23:04 | history | answered | Will Sawin | CC BY-SA 3.0 |