Skip to main content
6 events
when toggle format what by license comment
Jul 27, 2012 at 8:30 comment added Regula Krapf Yes, that is really confusing. Let $\nu$ be the generic point, then $k[\nu] = \mathcal{O}_{X,\nu} / \mathcal{m}_{\nu}$ where $\mathcal{m}_{\nu}$ is the maximal ideal corresponding to the generic point.
Jul 26, 2012 at 18:00 comment added Georges Elencwajg I find your notations quite confusing : $y$ is both an indeterminate and a generic point, k[y] is a field ?
Jul 26, 2012 at 14:37 comment added Steven Landsburg If "it means to write XxRSpec(k[y])", then I'd say you're done.
Jul 26, 2012 at 8:25 comment added Regula Krapf It means to write X×RSpec(k[y]). My idea was to consider the affine cover U0= {x≠0}∩X and so on and then glue. But I'm not sure how to do this concretely.
Jul 26, 2012 at 7:19 comment added Jesko Hüttenhain By "computing" this fibre product, what exactly do you mean? What kind of data constitutes a computed fibre product, as opposed to writing $X\times_R\mathrm{Spec}(k[y])$?
Jul 26, 2012 at 7:04 history asked Regula Krapf CC BY-SA 3.0