Yes, it is consistent with AD. In $L(\mathbb{R})$, if AD holds then $\Theta$ injects into $\mathcal{P}(\mathbb{R})$, or equivalently, into $2^{\mathbb{R}}$. The OD sets of reals are Wadge-cofinal and $\Theta$ is regular, so we can define an injection $F : \Theta \to \mathcal{P}(\mathbb{R})$ by induction. Let $F(\alpha)$ be the $<_{OD}$-least OD set of reals with Wadge rank greater than the Wadge ranks of all the sets of reals $F(\gamma)$, $\gamma < \alpha$.
To see that in $L(\mathbb{R})$ the Wadge ranks of the OD sets of reals are cofinal, notice that every set of reals $A$ is OD from some real $y$, say $x \in A \iff \varphi[x,y,\alpha]$Going further, andwe can determine the OD setHartogs number $\lbrace (x,y) : \varphi[x,y,\alpha] \rbrace$ has Wadge rank at least that$\aleph(2^{\mathbb{R}})$ in all models of $A$.
Assuming $AD + V=L(\mathcal{P}(\mathbb{R}))$ the existence of an injection $\Theta \to \mathcal{P}(\mathbb{R})$ is equivalent. The proof splits into two cases corresponding to the length of the Solovay sequence being a successor ordinal or a limit ordinal. The meaning
If the length of this expression that we will use herethe Solovay sequence is a successor ordinal, this means that there is a single set of reals $A$ such that the $OD_A$ setsevery set of reals are Wadge-cofinal inis OD from $\mathcal{P}(\mathbb{R})$$A$ and a real.
If the Solovay sequence has successor length as witnessed by In this case $A$$\aleph(2^{\mathbb{R}})$ has the largest possible value, thennamely $\Theta$ is regular because$\Theta(2^{\mathbb{R}})$. Given a surjection $F : \mathcal{P}(\mathbb{R}) \to Z$ for any functionset $g: \mathbb{R} \to \Theta$ is bounded by the Wadge rank of$Z$ we can construct an injection $Z \to \mathcal{P}(\mathbb{R})$. Let $G(z)$ be the set of pairs $(x,y)$ of reals such that $y$ is in the $<_{OD_A}$-leastleast $OD_A$$OD_{A,x}$ set of reals with Wadge rank at least $g(x)$. So we can just modify the argument given for$B$ with $L(\mathbb{R})$ by adding$F(B) = z$ $A$ as a parameter(if it exists.)
ConverselyOn the other hand, if therethe length of the Solovay sequence is an injectiona limit ordinal then $F:\Theta \to \mathcal{P}(\mathbb{R})$, it must be Wadge-cofinal or else we would get an injection$\aleph(2^{\mathbb{R}})$ is equal to $\Theta \to \mathbb{R}$, which$\Theta$; that is impossible, to $\Theta(\mathbb{R})$. If We have $V = L(\mathcal{P}(\mathbb{R}))$ then$\aleph(2^{\mathbb{R}}) \ge \Theta$ on general grounds like you said in the question. But any function $F$$F : \Theta \to \mathcal{P}(\mathbb{R})$ is OD from a set $A$ of reals because $V=L(\mathcal{P}(\mathbb{R}))$, so itsthe range is a Wadge-cofinal collectionof $F$ consists of $OD_A$ sets of reals. The Solovay sequence has limit length, so the range of $F$ cannot be all of $\mathcal{P}(\mathbb{R})$.