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Jul 29, 2012 at 16:28 comment added B R Oh! That was very silly of me: I read the condition as "kernel" rather than "cokernel" (which seemed an odd condition, but I wasn't going to judge). I'm not familiar with the implications of this condition, so I can't be sure, but I think the answer should be "yes".
Jul 29, 2012 at 12:47 comment added mnr Thanks for the references! I work under the (very restrictive) condition that H is with finite and abelian cokernel in G.
Jul 23, 2012 at 16:23 history answered B R CC BY-SA 3.0