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Aug 23, 2012 at 2:33 comment added Rafe Mazzeo That is correct, though I guess you need to add a few details that the sequence of solutions $u_j$ which are bounded in $C^{2,\alpha}$ and convergent in $L^2$ (or, say, $C^2$) have limit which lies in $C^{2,\alpha}$.
Aug 23, 2012 at 1:19 comment added timur @Rafe: Can you please have a look at my answer? I think I found a way around the density problem.
Jul 29, 2012 at 3:21 comment added Yuchen Liu @YangMills: I mean roughly I use Rafe's method with a little difference: first use $L^2$-theory to find a weak solution $u$, then use Schauder estimate and continuity method to find a $C^{2,\alpha}$ solution $v$ locally, and their difference is a weak solution of $\Delta (u-v)=0$ hence $(u-v)$ is $C^\infty$. Therefore, $u$ is in $C^{2,\alpha}$.
Jul 28, 2012 at 16:03 comment added YangMills what do you mean by "my answer is based on your first attempt"?
Jul 28, 2012 at 2:49 comment added Yuchen Liu @Rafe Mazzeo: I think my answer is based on your first attempt: math.stackexchange.com/questions/172887/…
Jul 28, 2012 at 2:46 vote accept Yuchen Liu
Jul 20, 2012 at 21:09 history answered Rafe Mazzeo CC BY-SA 3.0