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Jul 20, 2012 at 13:04 comment added user25235 Thanks ! It's amusing that the same constant $\frac{q^2}{2q-1}$ appears here and also as the limit of the polynomial method in the Kakeya problem.
Jul 20, 2012 at 12:49 vote accept user25235
Jul 20, 2012 at 12:32 history answered Peter Mueller CC BY-SA 3.0