Timeline for Is the class of $k$-gonal curves dominant
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Aug 21, 2014 at 23:08 | comment | added | roy smith | @Ari: Over the complex numbers for instance, the composition of P^1-->X^(k) with the abel map to J(X), lifts through the universal cover of J(X), and such a lift is constant by the maximum principle. | |
| May 12, 2014 at 19:23 | comment | added | Michael Zieve | The final assertion in the answer should be that if $Y$ is $k$-gonal then $X$ is $\ell$-gonal for some $\ell\le k$. | |
| Jul 20, 2012 at 9:49 | history | edited | Angelo | CC BY-SA 3.0 |
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| Jul 19, 2012 at 13:42 | vote | accept | Ariyan Javanpeykar | ||
| Jul 19, 2012 at 13:42 | comment | added | Ariyan Javanpeykar | Thank you for your answer. I didn't realize that the existence of a non-constant morphism from $\mathbf{P}^1$ to $X^{(k)}$ implied the existence of a $g^1_k$ on $X$. | |
| Jul 19, 2012 at 12:31 | history | answered | Angelo | CC BY-SA 3.0 |