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Feb 16, 2023 at 10:46 answer added Elías Guisado Villalgordo timeline score: 0
Oct 16, 2012 at 12:54 answer added John Stalfos timeline score: 1
Jul 19, 2012 at 19:11 comment added David Carchedi Another comment along these lines: $E(F)$ can only be Hausdorff if $X$ is locally Hausdorff. Also, if $X$ is locally Hausdorff, then one can choose a covering by Hausdorff neighborhoods, and the canonical projection to $X$ from the disjoint union of the elements of this cover is a local homeomorphism, hence a sheaf. This generalizes Mike's example.
Jul 19, 2012 at 17:31 comment added Mike Shulman For what it's worth, in case anyone else is confused, here is an example of a well-supported sheaf on a non-Hausdorff space whose total space is Hausdorff. Let $X$ be the real line with a doubled origin, and let $E(F) = \mathbb{R} + \mathbb{R}$ with the two maps to $X$ being two "copies of the identity" one going through each copy of the origin. Then $E(F)$ is certainly Hausdorff and its map to $X$ is surjective, and it's easy to see that it is also a local homeomorphism.
Jul 17, 2012 at 17:05 answer added David Carchedi timeline score: 0
Jul 17, 2012 at 13:57 comment added David Carchedi Changed accordingly.
Jul 17, 2012 at 13:56 history edited David Carchedi CC BY-SA 3.0
edited title
Jul 17, 2012 at 12:12 comment added Martin Brandenburg I would like to suggest "Can one characterize Hausdorff étale spaces" as a title.
Jul 17, 2012 at 10:42 history asked David Carchedi CC BY-SA 3.0