Timeline for Ultraweak closure inside a closed ball
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 21, 2012 at 2:13 | vote | accept | Michael | ||
| Jul 17, 2012 at 1:14 | answer | added | Narutaka OZAWA | timeline score: 3 | |
| Jul 17, 2012 at 0:08 | comment | added | Michael | Thanks, do we need to suppose $S$ unital ? What if $S$ is just supposed to be convex ? | |
| Jul 16, 2012 at 14:16 | comment | added | Yulia Kuznetsova | If $S$ is self-adjoint, then yes: this is the Kaplansky density theorem. | |
| Jul 16, 2012 at 13:49 | history | edited | Michael | CC BY-SA 3.0 |
added 44 characters in body
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| Jul 16, 2012 at 13:48 | comment | added | Michael | Indeed, the case I'm interested in is when $S$ is a subalgebra of $\mathcal{B}(H)$. I modified the question. | |
| Jul 16, 2012 at 5:14 | comment | added | Andreas Thom | The equality does not hold in general. Take $S$ to be unit sphere in $H$. Then $\bar S=B_1$, whereas $S \cap B_r = \varnothing$ for $r<1$. Maybe you want $S$ convex? | |
| Jul 16, 2012 at 3:34 | history | asked | Michael | CC BY-SA 3.0 |