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Jul 16, 2012 at 22:04 answer added Mike Shulman timeline score: 16
Jul 16, 2012 at 19:44 history edited Mike Shulman
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Jul 16, 2012 at 11:05 comment added Ronnie Brown That is a reasonable suggestion, and concurs with +1 to deal with homotopies (for the strict structures of our fundamental higher groupoids), and another +1 to deal with the covering dimension. Of course Higgins and I have good reasons for using cubical rather than simplicial methods. Major features of the two strands of work are (i) that they deal with structured spaces (filtered or $n$-cubes), and (ii) that the construction of the corresponding "fundamental" object, essential to the work, is not straightforward.
Jul 15, 2012 at 22:28 answer added Akhil Mathew timeline score: 4
Jul 15, 2012 at 21:17 comment added Mike Shulman My guess would be that 3 is 1+2, where 1 is the dimension of the groupoids in question (the classical SvKT is about 1-groupoids) and 2 is a universal constant for $n$-colimits --- a colimit of $n$-groupoids can be calculated using coproducts and realizations of truncated simplicial objects (generalized coequalizers) with $n+2$ terms. If we were calculating the fundamental 0-groupoid $\pi_0$, we should only need 1- and 2-fold intersections, and similarly for fundamental $n$-groupoids we should expect to need up to $(n+2)$-fold intersections.
Jul 15, 2012 at 16:52 history asked Ronnie Brown CC BY-SA 3.0