Timeline for Are the following q-Genocchi numbers known?
Current License: CC BY-SA 3.0
6 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Sep 28, 2012 at 17:25 | answer | added | Serkan | timeline score: 1 | |
Jul 20, 2012 at 8:57 | comment | added | Johann Cigler | In the mean time I have seen that these q-Genocchi numbers are related to the usual $q-$tangent numbers ${T_{2n - 1}}(q)$ by ${(- q;q)_ {2n - 1}} {G_{2n}}(q) = [2n] {T_{2n - 1}}(q).$ | |
Jul 19, 2012 at 20:25 | history | edited | John Wiltshire-Gordon |
edited tags
|
|
Jul 15, 2012 at 6:45 | comment | added | Johann Cigler | The corresponding Seidel identity is $$\sum{(-1)^k}q^{\binom{2k}{2}} {n\brack{2k}}{{(-q^{n-2k+1};q)_{2k}}}/ {{(-q^{2n-2k};q)_{2k}}}{G_{2n-2k}}(q) =[n=1].$$ | |
Jul 14, 2012 at 22:41 | comment | added | Zack Wolske | Is this the same as the q-analog you get by rewriting $\sum_{k=0}^{\lfloor \frac{n}{2} \rfloor} (-1)^k {n \choose 2k}G_{2n-k} = 0$ to a relation involving q-binomial coefficients? | |
Jul 14, 2012 at 14:33 | history | asked | Johann Cigler | CC BY-SA 3.0 |