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Jul 11, 2012 at 20:30 vote accept Evgeny
Jul 11, 2012 at 20:11 answer added Lee Mosher timeline score: 1
Jul 11, 2012 at 19:42 history edited Evgeny CC BY-SA 3.0
Corrected bad notation of objects
Jul 11, 2012 at 19:40 comment added Evgeny Sorry, but the last part of your construction seems to be vague for me. Is it possible that (in your example) image could be contained in a bigger cone?
Jul 11, 2012 at 18:33 comment added Lee Mosher It is easy enough to construct a counterexample. $h$ will take the sphere of radius $1/3$ to itself, and will preserve the intersection of that sphere with the set $X_{C^*}$. Also, $h$ will take the sphere of radius $2/3$ to itself, but the $h$-image of the intersection of that sphere with the set $X_{C^*}$ will contain the intersection of that sphere with the complementary set $R^3 - X_{C^*}$.
Jul 11, 2012 at 17:40 comment added Evgeny In context of my interest it is enough that $h$ maps cone into another cone, I even don't need $h(X_{C^*}) = h(X_{C'}) or $C^* = C'$.
Jul 11, 2012 at 17:31 comment added HorizonsMaths I guess you meant $h(X_{C^*}) \subseteq X_{C^*}$!
Jul 11, 2012 at 17:07 history edited Evgeny CC BY-SA 3.0
added 20 characters in body
Jul 11, 2012 at 17:05 comment added Evgeny That question appeared in my research, so I just wanted to check is this a common fact (that I've missed in my education) or should I cope with that question myself.
Jul 11, 2012 at 17:00 comment added Evgeny Yes, I meant that. Sorry, I'll correct this moment
Jul 11, 2012 at 16:59 comment added Lee Mosher Whether it does or not, though, this questions seems to me to be more suited to other sites such as math.stackexchange.com. It is not a research level question, which is what Math Overflow is for, as you will see if you read the faq.
Jul 11, 2012 at 16:35 comment added Lee Mosher Does $Oz$ mean the $z$-axis intersected with the ball $B$?
Jul 11, 2012 at 16:21 history asked Evgeny CC BY-SA 3.0