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Jul 11, 2012 at 13:17 vote accept Justin Smith
Jul 11, 2012 at 13:18
Jul 10, 2012 at 17:30 comment added Emerton Dear Jurgen, What you are calling $\mathbb{RP}^1$ is the real points of $\mathbb P^1$, which is not at all the same thing as the variety or scheme $\mathbb P^1$ over $\mathbb R$. Thus there is not contradiction. (If we consider your stated isomorphism, the non-constant functions $x$ and $y$ are defined over $\mathbb R$, and they will have poles on $\mathbb P^1$, but not at any real point; rather the poles will be at complex conjugate pairs of complex points.) Regards,
Jul 10, 2012 at 14:25 history answered Jürgen Böhm CC BY-SA 3.0