Skip to main content

Timeline for "You can't push a rope" [closed]

Current License: CC BY-SA 3.0

20 events
when toggle format what by license comment
Feb 14, 2016 at 18:37 comment added Ben McKay en.wikipedia.org/wiki/Pushing_on_a_string
Feb 14, 2016 at 18:21 history closed Mikhail Katz
Franz Lemmermeyer
Chris Godsil
Stefan Kohl
Felipe Voloch
Not suitable for this site
Feb 14, 2016 at 15:11 review Close votes
Feb 14, 2016 at 18:21
Feb 14, 2016 at 15:07 answer added Michael Renardy timeline score: 10
Feb 14, 2016 at 15:05 history made wiki Post Made Community Wiki by Todd Trimble
Feb 14, 2016 at 14:27 answer added Bob R Cherry timeline score: 1
Dec 11, 2015 at 13:33 answer added Jack timeline score: 4
Jul 17, 2012 at 8:59 comment added Federico Poloni @S. Carnahan: in my comment I meant a rope on an Euclidean plane, without gravity. It is not clear to me whether it is possible or not: for instance, with n=2 points it should be equivalent to the classical "how to balance a rod on your nose" example problem in control theory.
Jul 17, 2012 at 5:40 answer added dab timeline score: 6
Jul 11, 2012 at 5:01 comment added S. Carnahan @Federico Poloni: You could put the rope in a nearly-frictionless trough with a "V"-shaped cross-section. (Also, I think most real-life ropes have small but nonzero restoring forces, due to their nonzero cross-section).
Jul 10, 2012 at 14:07 comment added Federico Poloni Actually, it would be interesting to solve it as a control theory problem. Model a rope as a large number of points connected by short incompressible rods, and suppose that initially they are perfectly aligned and horizontal. Then you can "push the rope" by applying a horizontal force which will be propagated through the rods. But this is an unstable equilibrium; is it possible to determine vertical "control" forces that keep the rope in a neighbourhood of the unstable equilibrium point, while pushing the rope horizontally at the same time?
Jul 10, 2012 at 12:55 comment added Boris Bukh @Alexander: Веревку невозможно толкать.
Jul 10, 2012 at 10:03 comment added Alexander Chervov How this should be translated into Russian ? "Вы не можете нажать на веревке" - translate.google.com - does not make sense for me ...
Jul 10, 2012 at 8:46 comment added Asaf Karagila I remember once pushing a rope when it was on the ground... perhaps the saying has a second part "unless it is on the ground". :-)
Jul 10, 2012 at 7:59 history edited David Feldman CC BY-SA 3.0
deleted 1 characters in body
Jul 10, 2012 at 7:44 comment added Douglas Zare I have no background in engineering, but I remember saying "You are pushing on a rope," a few times. Rather than something deep, I think these boiled down to $P \implies Q. ~Q \therefore ~...$
Jul 10, 2012 at 7:26 comment added David Feldman Amit Kumar Gupta, that is certainly useful for me to hear! Of course a solid beam has few significant internal degrees of freedom, so a small state space, and just the opposite for a rope. So to me the literal interpretation seems paradigmatic for any situation where a long causal chain has small errors that will accumulate and overwhelm the desired effect or signal. I first heard this decades ago from an MIT student who definitely thought he was getting a broad message, but one he couldn't quite explain to me.
Jul 10, 2012 at 7:09 comment added Amit Kumar Gupta When I was an engineering student, I had a professor who said it, and meant it literally. I remember drawing structure diagrams with arrows representing forces at all the nodes. A solid beam could have compression and tension forces at either end, but ropes or cables could only have tension.
Jul 10, 2012 at 7:08 comment added Johan Wästlund Perhaps you can post it as an answer to mathoverflow.net/questions/3559/… and wait for comments ;)
Jul 10, 2012 at 6:31 history asked David Feldman CC BY-SA 3.0