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Dec 30, 2009 at 23:05 history edited Deane Yang CC BY-SA 2.5
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Dec 30, 2009 at 20:28 comment added macbeth In fact, I don't think the first claim is right at all. For instance, there's a surjective, not-injective local diffeomorphism from $\mathbb{R}^2$ to $S^2$: you can wind an infinitely long rubber ribbon around a ball so as to cover it completely.
Dec 30, 2009 at 19:54 comment added macbeth The first claim doesn't seem quite right; I think you need (at least) surjectivity of f as well. For instance there are local diffeomorphisms from the interval (0, 2) to itself, with image (0, 1).
Dec 30, 2009 at 19:27 comment added Georges Elencwajg If f:X--->Y is a local homeomorphism between hausdorff topological spaces, then f is a finite covering if and only f is proper. Hence if moreover Y is simply connected and X connected, a proper local homeomorphism will be a homeomorphism. (No assumption of simple connectedness is needed for X)
Dec 30, 2009 at 18:56 history answered Deane Yang CC BY-SA 2.5