Timeline for Going in the direction of the gradient
Current License: CC BY-SA 3.0
5 events
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| Apr 13, 2017 at 12:19 | history | edited | CommunityBot |
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| Jul 9, 2012 at 9:21 | comment | added | user21162 | No, $x(t)$ should be driven to the minimum of $f(x)$ on ${\cal G}$, which is the set of minimizers of $g$ (at least, that is what I think should be true!) For example, in the example I gave in the final paragraph, the set of minimizers of $g$ is the set $x_1+x_2=2$ and the minimum of $f$ on it is $(1,1)$ - which is where indeed the solution appears to go numerically. | |
| Jul 9, 2012 at 9:02 | comment | added | Denis Serre | Do you mean instead that $x(t)$ is driven to the minimum of $g$ ? | |
| Jul 8, 2012 at 14:39 | answer | added | Anton Petrunin | timeline score: 1 | |
| Jul 8, 2012 at 13:20 | history | asked | user21162 | CC BY-SA 3.0 |