Timeline for Closed reductive sub-orbits
Current License: CC BY-SA 4.0
16 events
| when toggle format | what | by | license | comment | |
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| Aug 27, 2020 at 17:30 | history | edited | YCor | CC BY-SA 4.0 |
removed capitals from title (the question was bumped anyway)
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| Jul 8, 2012 at 19:35 | history | edited | Sean Lawton | CC BY-SA 3.0 |
added 64 characters in body
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| Jul 8, 2012 at 19:17 | comment | added | Sean Lawton | It is not necessary to appeal to maximal compact subgroups to define the class of groups I had in mind, however, given the confusion I caused originally, I thought it might help to use this (equivalent over $\mathbb{C}$) way of describing what I had in mind. Sorry if that caused additional confusion. | |
| Jul 8, 2012 at 19:14 | history | edited | Sean Lawton | CC BY-SA 3.0 |
added 163 characters in body
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| Jul 7, 2012 at 18:47 | vote | accept | Sean Lawton | ||
| Jul 7, 2012 at 14:28 | answer | added | Jim Humphreys | timeline score: 4 | |
| Jul 6, 2012 at 22:15 | answer | added | Adam | timeline score: 8 | |
| Jul 6, 2012 at 20:28 | history | edited | Sean Lawton | CC BY-SA 3.0 |
added 195 characters in body
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| Jul 6, 2012 at 20:26 | comment | added | Sean Lawton | Sorry, $K$ is a maximal compact subgroup of $G$. | |
| Jul 6, 2012 at 20:26 | comment | added | Sean Lawton | I mean that $H$ is the Zariski closure of a compact subgroup of K. Sorry, it appears I left that off originally. I will edit if possible. | |
| Jul 6, 2012 at 20:10 | comment | added | Jason Starr | @Sean "... same for $H$ but as a subgroup ..." What precisely do you mean by this. For instance, in the corrected example I give, $H$ is not a reductive subgroup of $G$. | |
| Jul 6, 2012 at 19:27 | comment | added | Sean Lawton | First, thanks for the interest Jim. I am not assuming $G$ is connected. I am assuming that $G$ is an algebraic $\mathbb{C}$-group that is the Zariski closure of a maximal compact subgroup (same for $H$ but as a subgroup). | |
| Jul 6, 2012 at 15:48 | comment | added | Jim Humphreys | I just added a tag. The question itself could use more precision: I'm assuming the group is connected, while the subgroup is any closed (and maybe also connected?) subgroup, relative to the Zariski topology. | |
| Jul 6, 2012 at 15:46 | history | edited | Jim Humphreys |
edited tags
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| Jul 6, 2012 at 15:06 | answer | added | Jason Starr | timeline score: 4 | |
| Jul 6, 2012 at 14:47 | history | asked | Sean Lawton | CC BY-SA 3.0 |