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Jul 6, 2012 at 12:24 comment added Tom Goodwillie Your question was about spectra with $G$-action. There was no need to mention genuine $G$-spectra in the question. The remarkable thing is they come into the answer in an essential way.
Jul 6, 2012 at 0:39 comment added Akhil Mathew Sure. I've been a bit loose about this in the question. I'll take a look at the equivariant homotopy book so that I can understand these distinctions.
Jul 4, 2012 at 19:52 history answered Peter May CC BY-SA 3.0