Skip to main content
6 events
when toggle format what by license comment
Dec 21, 2016 at 10:14 vote accept Luigi Scorzato
Dec 15, 2016 at 2:08 history edited Robert Bryant
edited tags
Dec 15, 2016 at 1:15 answer added Robert Bryant timeline score: 2
Oct 17, 2012 at 22:15 comment added Bob Terrell Does $B$ "skew-symmetric" mean that $B^T=-B$, or is it conjugate transpose $B^* = -B$? And is $A$ real?
Jul 3, 2012 at 16:46 comment added Denis Serre You're right. My answer was an error. Even if we split the system into real and imaginary parts, we obtain a $2n\times$-system of which we know only $n$ solutions, given by the real/imaginary parts of the columns of $\Phi$. This is insufficient to get any information. The point is that because your system is not $\mathbb C$-linear, but only $\mathbb R$-linear, you need a list of $2n$ solutions (instead of $n$), to write something non-trivial. Think about the scalar case $n=1$ : you can't give $y(t)$ in terms of $y(0)$ in close form.
Jul 3, 2012 at 9:23 history asked Luigi Scorzato CC BY-SA 3.0