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S Jan 15, 2015 at 8:22 history bounty ended CommunityBot
S Jan 15, 2015 at 8:22 history notice removed CommunityBot
Jan 14, 2015 at 4:36 answer added Gjergji Zaimi timeline score: 3
Jan 12, 2015 at 14:35 answer added Abdelmalek Abdesselam timeline score: 1
S Jan 7, 2015 at 7:03 history bounty started მამუკა ჯიბლაძე
S Jan 7, 2015 at 7:03 history notice added მამუკა ჯიბლაძე Draw attention
Apr 8, 2014 at 7:24 comment added მამუკა ჯიბლაძე I am not sure if this might lead to anything but $$ \sum_{n\geqslant0}\frac{e^{nz}e^{n^2t}}{n!}=e\sum_{k,l\geqslant0} \frac{{B_{k+2l}}}{{k!l!(k+l)!}}z^kt^l $$ where the $B$'s are the Bell numbers...
Jul 3, 2012 at 18:49 comment added Gerald Edgar So writing $g(u)=f(\exp(u))$, Ira's equation becomes a "delay differential equation" where the derivative $g'(u)$ is written in terms of $g(u-\tau)$, for some $\tau$.
Jul 3, 2012 at 17:58 comment added Federico Ardila Ira, I did mean that, and I corrected it in the post. (I hope that's proper math overflow etiquette.)
Jul 3, 2012 at 17:56 history edited Federico Ardila CC BY-SA 3.0
corrected a typo in the formula; deleted 3 characters in body
Jul 3, 2012 at 17:17 comment added Ira Gessel The generating function $f(x) = \sum_n x^n y^\binom{n}{2}/n!$ satisfies $f'(x) = f(xy)$.
Jul 3, 2012 at 17:03 comment added Martin Rubey Is it known whether $\sum x^n y^{n^2} / {n!}$ satisfies an ADE?
Jul 3, 2012 at 13:39 comment added Ira Gessel Don't you mean $\sum_n x^n y^{n^2}/n!$?
Jul 3, 2012 at 1:06 history edited Federico Ardila CC BY-SA 3.0
added 57 characters in body
Jul 3, 2012 at 0:58 comment added Qiaochu Yuan en.wikipedia.org/wiki/Theta_function
Jul 3, 2012 at 0:48 history asked Federico Ardila CC BY-SA 3.0